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javascript:Bing Maps AJAX Control, Version 7.0
阅读量:7126 次
发布时间:2019-06-28

本文共 3995 字,大约阅读时间需要 13 分钟。

         Map with valid credentials      

  

http://www.codeproject.com/Articles/79123/Sample-WPF-Application-Consuming-Bing-Maps-Web-Ser

 

Namespace Address
GeocodeService
SearchService
ImageryService
RouteService

 

Supported Cultures

The following table lists supported cultures for map labels, the navigation control and the  module. The Culture column lists values to specify for the mkt parameter.

 

Language - Country/Region Culture Map Labels Navigation Control Microsoft.Maps.Directions module

All

ngt

X

   

Czech – Czech Republic

cs-CZ

X

 

X

Danish – Denmark

da-DK

X

 

X

Dutch - Belgium

nl-BE

X

X

 

Dutch – Netherlands

nl-NL

X

X

X

English - Australia

en-AU

X

 

X

English – Canada

en-CA

X

X

X

English - India

en-IN

X

X

X

English - United Kingdom

en-GB

X

X

X

English - United States

en-US

X

X

X

Finnish – Finland

fi-FI

X

 

X

French-Belgium

fr-BE

X

X

 

French – Canada

fr-CA

X

X

X

French-Switzerland

fr-CH

X

X

 

French – France

fr-FR

X

X

X

German – Germany

de-DE

X

X

X

Italian – Italy

it-IT

X

X

X

Japanese - Japan

ja-JP

X

X

X

Korean-Korea

Ko-KR

X

X

 

Norwegian (Bokmal) - Norway

nb-NO

X

X

X

Polish - Poland

pl-PL

X

X

X

Portuguese - Brazil

pt-BR

X

 

X

Portuguese - Portugal

pt-PT

X

 

X

Russian - Russia

ru-RU

X

X

X

Spanish - Mexico

es-MX

X

X

X

Spanish - Spain

es-ES

X

X

X

Spanish – United States

es-US

X

X

X

Swedish - Sweden

sv-SE

X

X

X

Chinese – Hong Kong

zh - HK

X

X

X

Chinese - Taiwan

zh - TW

X

X

X

 

     Bing Map Demo                                  
BLOG

  http://stevewellens.com/GoogleMapsDemo.html?ckattempt=2

http://stevewellens.com/BingMapsDemo.html?ckattempt=1

http://vejs.codeplex.com/

https://www.microsoft.com/maps/choose-your-bing-maps-API.aspx

https://www.bingmapsportal.com/ISDK/AjaxV7#TrafficModule1

http://cn.bing.com/dev/en-us/dev-center

https://code.msdn.microsoft.com/site/search?f%5B0%5D.Type=SearchText&f%5B0%5D.Value=bing%20maps

http://microsoft.github.io/windows/

https://code.msdn.microsoft.com/bing/Bing-Maps-for-JavaScript-84f1effc

https://msdn.microsoft.com/en-us/library/ff701733.aspx

http://www.codeproject.com/Articles/461691/Driving-route-path-direction-with-Bing-Maps-in-Csh

 

国测局GCJ-02坐标体系(谷歌、高德、腾讯、微软、雅虎等),与百度坐标BD-09体系的转换,在CSDN上有很详细的讲解:

C++:

const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;    void bd_encrypt(double gg_lat, double gg_lon, double &bd_lat, double &bd_lon)  {      double x = gg_lon, y = gg_lat;      double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi);      double theta = atan2(y, x) + 0.000003 * cos(x * x_pi);      bd_lon = z * cos(theta) + 0.0065;      bd_lat = z * sin(theta) + 0.006;  }    void bd_decrypt(double bd_lat, double bd_lon, double &gg_lat, double &gg_lon)  {      double x = bd_lon - 0.0065, y = bd_lat - 0.006;      double z = sqrt(x * x + y * y) - 0.00002 * sin(y * x_pi);      double theta = atan2(y, x) - 0.000003 * cos(x * x_pi);      gg_lon = z * cos(theta);      gg_lat = z * sin(theta);  }

  csharp:

const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;          ///         ///         ///         ///         ///         ///         ///         void bd_encrypt(double gg_lat, double gg_lon,out double bd_lat,out double bd_lon)          {              double x = gg_lon, y = gg_lat;            double z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * x_pi);            double theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * x_pi);            bd_lon = z * Math.Cos(theta) + 0.0065;            bd_lat = z * Math.Sin(theta) + 0.006;                                  }          ///         ///         ///         ///         ///         ///         ///         void bd_decrypt(double bd_lat, double bd_lon,out double gg_lat,out double gg_lon)          {              double x = bd_lon - 0.0065, y = bd_lat - 0.006;            double z = Math.Sqrt(x * x + y * y) - 0.00002 * Math.Sin(y * x_pi);            double theta = Math.Atan2(y, x) - 0.000003 * Math.Cos(x * x_pi);            gg_lon = z * Math.Cos(theta);            gg_lat = z * Math.Sin(theta);          }

  

 

转载地址:http://grhel.baihongyu.com/

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